भारतकोश
पञ्चसिद्धान्तिका (आचार्य वराहमिहिर - सूर्य, रोमक, पौलिश, वासिष्ठ एवं पितामह सिद्धान्त)

पञ्चसिद्धान्तिका (आचार्य वराहमिहिर - सूर्य, रोमक, पौलिश, वासिष्ठ एवं पितामह सिद्धान्त)

Panchasiddhantika of Acharya Varahamihira with Commentary

आचार्य वराहमिहिर द्वारा

DevanagariHindipublished419 पृष्ठ

पृष्ठ 121, कुल 419 में से

संदर्भ में पढ़ें
पृष्ठ 121

IV. 22 IV. THREE PROBLEMS 95 [मध्याह्नच्छाया] अपमोनयुताऽक्षज्यां त्रिज्यात्कृतिविशेषमूलेन । छिन्द्याद् द्वादशगुणितां लब्धा माध्याह्निकी छाया ॥ २२ ॥ Sine zenith distance 22. Subtract the Sun’s declination from the latitude (of the place), if the decli- nation is north, and add if it is south. The midday Sun’s Z.D. is got. Find its sine and multiply by twelve. Divide this by the root of the difference of the squares of the radius and sine ZD. The mid-day shadow is obtained in aṅgulas. The following are the rules: i. Degrees of zenith distance = Latitude ∓ Sun’s declination (the upper sign being used for north declination and the lower for the south.) ii. Mid-day shadow = 12 × sin ZD ÷ √120² − sin² ZD (where 120 is written for radius). It must be noted that the incompleteness mentioned in connection with the second formula if the previous work is found here too. Example 6. The latitude of a place is 25° 9′. The Sun’s declination is 11° 44′ , south, (the Sun being in the part of the ecliptic beginning from Libra). Find the mid-day shadow. The declination being south, ZD = 25° 9′ + 11° 44′ = 36° 52′. Sin ZD = 72′. ∴ Midday shadow = 12 × 72 ÷ √120² − 72² = 12 × 72 ÷ 96 = 9 aṅgulas. The rules are explained thus: From the previous rule, Latitude = zenith distance ± declination, (+ for north declination, and − for south declination), we have, zenith distance = latitude ∓ declination, (for north and south declinations, respectively). From this sine zenith distance is got. Using this, the shadow is obtained from the previous rule, sin ZD = shadow × 120 ÷ √shadow² + 144. Squaring both sides, sin² ZD = shadow² × 120² ÷ (shadow² + 144). sin² ZD × (shadow² + 144) = shadow² × 120² sin² ZD × shadow² + 144 sin² ZD = shadow² × 120² 120². shadow² − sin² ZD. shadow² = 144 sin² ZD shadow² = 144 sin² ZD ÷ (120² − sin² ZD) shadow = 12 sin ZD ÷ √120² − sin² ZD. 22. Quoted by Utpala on BS 2, p. 61. 22a. A.D. अपनोन. A.C.D. U. ॰क्षज्या c. A.C.D. गुणिता b. A. तांत्रिकृति; C.D. U. तत्तिर्ज्याकृति. A. मूला d. A. माध्याह्नकी