पञ्चसिद्धान्तिका (आचार्य वराहमिहिर - सूर्य, रोमक, पौलिश, वासिष्ठ एवं पितामह सिद्धान्त)
Panchasiddhantika of Acharya Varahamihira with Commentary
आचार्य वराहमिहिर द्वारा
पृष्ठ 55, कुल 419 में से
संदर्भ में पढ़ेंII.6 II. VĀSIṢṬHA-SIDDHĀNTA 29 The two formulae can be written down thus: (i) If P is the number of plus-padas, {1094 + 5(P − 1)} P/63. (ii) If P' is the number of minus-padas, {2414 − 5(P' − 1)} P'/63. Example 3. Continue Ex.2 and compute the true Moon for the days given. The mean Moon got in Ex. 2 to the end of the gati = 4ʳ 24° 4' The padas obtained are 64, plus-padas (P) Adding degrees equal to P = 64, + 2 4 0 Using formula (i) intended for plus-padas, {1094 + 5 (64 − 1)} 64/63 = 1431 minutes + 0 23 51 —————————————————————————————————————————————————————————— The true Moon 7 21 55 Example 4. The Days from Epoch are 1219. Find the True Moon. 1219 + 1936 = 3155 (= days for computation). Dividing by 3031, ghana got is 1, remainder 124. Multiplying 124 by 9 and dividing by 248, the gatis got are 4. The remainder 124 are padas. This is just one half-gati and no pada is left over. r ° ' Ghana 1 × ¾ = 0ʳ 22° 30'. Deducting from 12 rāśis = 11 7 30 Adding minutes 1 × 2 + 0 0 2 Kṣepa + 1 7 29 Gatis 4, × 184 9/10 = 740 (minutes) + 0 12 20 For the half-gati, add + 6 0 4 —————————————————————————————————————————————————————————— True Moon 6 27 25 Example 5. Find the true Moon for Days from Epoch, 1228. 1228 + 1936 = 3164 (= days for computation). Dividing by 3031, ghanas got 1, remainder 133. Multiplying by 9 and dividing by 248, the quotient 4 are the gatis got, and the remainder 205 are padas left over. A half-gati (= 124 padas) can be taken from this, and the remaining 81 are minus- padas. r ° ' ghana 1 × ¾ʳ = 0ʳ 22° 30'. Deducting from 12 rāśis 11 7 30 Adding 1 × 2 minutes + 0 0 2 Adding kṣepa + 1 7 29 Gatis, 4, × 184 9/10 = 740 (minutes) + 0 12 20 For the half-gati + 6 0 4 Degrees equal to P' = 81' + 2 21 0 Using formula (ii) (as the left over are minus-padas = P'), 2414 − 5 (81 − 1) 81/63 = 2589 mts. + 1 13 9 —————————————————————————————————————————————————————————— True Moon 11 1 34 The following is the explanation of the processes: The true Moon at a given time t is: (i) the mean Moon at t plus (ii) the equation of the centre for t. (i) is given here in five parts. We shall call them (a), (b), (c), (d), (e) which are to be added up to get the total mean Moon.