सिद्धान्तशिरोमणि: गणिताध्याय (भास्कराचार्य - ग्रहगणित, मध्यमाधिकार व स्पष्टाधिकार सटीक)

160 Kendras on two consecutive days whereas Madhyakendragati ^ is P₁E₂P₂. Also, we have the equation. Sīghra — Sphutagraha = Sphutakendra so that Sīghra- gati — Sphutagati = Sphuta- kendragati. Hence Sphutagati = Sīghragati — Sphutakendra- Fig. 16 gati. So we have now to seek the value of P₁Ê₂P₂. Let P₁a stand for the Sīghra- phala of the first day which is equal to e f, f being the true planet of the first day. E₂ d will be parallel to E₁ f because P₁ e being parallel to E₁ E₂ and e f being equal to P₁ d, d f 11 P₁ e (parallels to E₁ E₂ cut off equal arcs on the two circles). This may be seen also as follows. Since P₁ d is taken to be equal to e f, e being the mean planet and f the true on the first day e Ê₁ f = P₁ Ê₂ d. But E₁ e 11 E₂ P₁ ∴ e E₁ f = E₁ P̂₁ E₂ ∴ P₁ Ê₂ d = E₁ P̂₁ E₂ and alter- nate angles being equal E₁ P₁ 11 E₂d. P₁ a is the H sine of P₁ d where P₂ b is the H sine P₂ d. Looking upon P₁P₂ as an increment in P₁ d i.e. looking upon the Kendragati P₁ Ê₂ P₂ as an increment in Sīghraphala, Bhāskara uses the method of Bhogyakhanda sphuti Karana to obtain the Sphutakendragati. From the figure. P₂c = P₂b — P₁a = H sin (G + δm) — H sin E H sin E H cos δm + H cos E H sin δm = ————————————————————————————————————— — H sin E R