सिद्धान्तशिरोमणि: गणिताध्याय (भास्कराचार्य - ग्रहगणित, मध्यमाधिकार व स्पष्टाधिकार सटीक)

164 From III & IV cos ξ / cos θ = (r cos ϕ − R) / (R cos ϕ − r) V Equating cos ξ / cos θ from II and V − u / v = (r cos ϕ − R) / (R cos ϕ − r) so that (ru + Rv) / (rv + Ru) = cos ϕ If m be the Śīghra anomaly m = 180 − ϕ so that cos m = − (ru + Rv) / (rv + Ru) VI Now we shall show that Bhāskara's formula accords with this Spaṣṭagati = Śīghragati − (H cos E δm) / K . As per Bhāskara Spaṣṭagati = 0 if Śīghragati = (H cos E δm) / K VII ie. Jupiter appears stationary as seen from Earth, if Śīghra- gati = (H cos E δm) / K The angular velocities of Earth and Jupiter are respect- ively u / r and v / R so that the Sun's apparent velocity is also u / r and δm = Kēndra gati = Sun's apparent velocity minus Jupiter's heliocentric velocity = u / r − v / R ∴ Substituting in VII Śīghragati = u / r = (H cos E / K) (u / r − v / R) ∴ u / r ( (H cos E / K) − 1 ) = (H cos E / K) × v / R ie. u / r ( (H cos E − K) / K ) = (H cos E / K) × v / R