सिद्धान्तशिरोमणि: गणिताध्याय (भास्कराचार्य - ग्रहगणित, मध्यमाधिकार व स्पष्टाधिकार सटीक)
Siddhanta Shiromani Ganitadhyaya of Bhaskaracharya with Commentary
भास्कराचार्य द्वितीय द्वारा
पृष्ठ 321, कुल 573 में से
संदर्भ में पढ़ें301 Bhāskara’s proof of I.A. = kR² / (H cos δ × I.K.) proceeds from first principles as follows :—(i) If by k we have 12 as the Koṭi what have we for R? The result is H cos z, Mahāśaṅku. ∴ Mahā Śaṅku = 12 R / I.K. From Mahā Śaṅku we pass on to Iṣṭa Hṛti with which it forms a latitudinal triangle. If by the gnomon of 12 units we have k the Viṣuvat Karṇa, what have we by Mahā Śaṅku? The result is (12 R / I.K.) × (k / 12) = kR / I.K. Again from the Iṣṭa-Hṛti we pass on to I.A. by multiplying by R / (H cos δ) so that I.A. = kR² / (H cos δ × I.K.) as given. Second half of verse 68. The inverse Hversine if a quantity x greater than R, is 5400 + H sin ⁻¹ (θ) when x - R = θ. Comm. Since Hvers (90 + θ) = R + H sin θ = x (say) 90 + θ = Hvers ⁻¹ (R + H sin θ) = But 90° are equal to 5400 asus and θ = H sin ⁻¹ (H sin θ) = H sin ⁻¹ (x - R) = त्रिज्याधिकभागस्यक्रमचापम् ∴ 5400 + त्रिज्याधिकभागक्रमचापम् = Utkrama Cāpa of a त्रिज्यादिक quantity. Verse 69. Alternate method of obtaining the time that has elapsed after Sunrise noting the shadow S. Subtract Charajyā from or add it to Iṣṭāntyā according as δ is north or south. Obtain inverse H sine of the remainder and add the Caracāpa to this inverse H sine. Then we have the unnatakāla by converting the result into time.