सिद्धान्तशिरोमणि: गणिताध्याय (भास्कराचार्य - ग्रहगणित, मध्यमाधिकार व स्पष्टाधिकार सटीक)
Siddhanta Shiromani Ganitadhyaya of Bhaskaracharya with Commentary
भास्कराचार्य द्वितीय द्वारा
पृष्ठ 340, कुल 573 में से
संदर्भ में पढ़ें320 (4) Or again in the given place, for the value of H cos δ to be valid the Unnatakāla x must be such that 15 H sin x > 13 R so that H cos δ might be less than R. This means sin x > 13/15 = .8667 so that x > 60°—4' ; so instead of 10 nādīkas, if the time were given to be just even one Vinādika greater, it would have been alright, or again if the latitude were given to be just a little less it would have been alright. Verse 92. Oh ! Mathematician ! please tell me the magnitudes of the equinoctial shadow and the longitude of the Sun if at a place on a particular day, Kujyā is 245 and Taddhṛti 3125. Verse 93. Answer to the questiou above. s = √[ 144 Kujyā / (Taddhṛti—Kujyā) ] and H sid δ = (12 Kujyā) / s and H sin λ = (R H sin δ) / (H sin ω) . Comm. From the fifth latitudinal triangle compared with third, Kujyā / Krāntijyā = Krāntijyā / (Taddhṛti — Kujyā) = Agrā / S. S. = s / 12 (1) (2) (3) (4) Multiplying (1) by (2) Kujyā / (Taddhṛti — Kujyā) = s² / 12² ∴ s = √[ 144 Kujyā / (Taddhṛti — Kujyā) ] Also Equating (1) and (4) Krāntijyā = (12 / s) Kujyā. Verse 94. Given that H sin δ + S. S. + Taddhṛti—Kujyā = 6720, and Kujyā + Agrā + H sin δ = 1960. Then I shall consider him who finds s and the longitude of the Sun as the very Sun illuminating the lotuses of astronomers.