सिद्धान्तशिरोमणि: गणिताध्याय (भास्कराचार्य - ग्रहगणित, मध्यमाधिकार व स्पष्टाधिकार सटीक)

328 Agrā / s = S. S. / 12 = Taddhṛti / k = (Agrā + S. S. + Taddhṛti) / (s + 12 + k) (1) (2) (3) = 1800 / (9 + 12 + 15) = 1800 / 36 = 50 II (4) Equating (1) and (4) Agrā = 9 × 50 = 450 Equating (2) and (4) S. S. = 12 × 50 = 600 Thirdly Taddhṛti = 15 × 50 = 750 Again Equating (1) and (6) of I Agrā / Krāntijyā = 5 / 4 = 450 / Krāntijyā ∴ H sin δ = (450 × 4) / 5 = 360 from which λ could be computed. Verse 98. The chara at a place where s = 9, is equal to 3 nādis. If you could compute the longitude of the Sun, then certainly you are a leader among astronomers, Oh ! Scholar ! Verse 99. Answer to the problem above. 12 Carajyā / √((12 × Carajyā / R)² + s²) = H sin δ where from λ the longitude of the Sun could be computed. Comm. Let H sin δ = x; then from the third lati- tudinal triangle Kujyā / Krāntijyā = s / 12 = 9 / 12 = 3 / 4 ∴ Kujyā = 3 x / 4 since Krāntijyā means H sin δ ∴ Carajyā = 3 x / 4 × R / (H cos δ) = 3 R x / (4 √(R² - x²)) = H sin (3 × 6) = H sin 18° ∴ Squaring 9 R² x² = 16 (R² - x²) H sin² 18 = 16 Carajyā² (R² - x²)