भारतकोश
सिद्धान्तशिरोमणि: गणिताध्याय (भास्कराचार्य - ग्रहगणित, मध्यमाधिकार व स्पष्टाधिकार सटीक)

सिद्धान्तशिरोमणि: गणिताध्याय (भास्कराचार्य - ग्रहगणित, मध्यमाधिकार व स्पष्टाधिकार सटीक)

Siddhanta Shiromani Ganitadhyaya of Bhaskaracharya with Commentary

भास्कराचार्य द्वितीय द्वारा

DevanagariHindipublished573 पृष्ठ

पृष्ठ 356, कुल 573 में से

संदर्भ में पढ़ें
पृष्ठ 356

336 and s and m the angular semidiameters of the Sun and the Moon. (This formnla we shall see later). This higher limit comes to 88.5'. The limit of 56' for the occurence of a lunar eclipse is the value of pm + ps — s + m as we shall see later. The latitude of 56' of the Moon arises out of a longi- tude of 12° of the Moon with respect to a node, whereas the latitude of 32' arises out of a longitude of 7° with respect to the node. Since at an eclipse solar or lunar, the longitude of the Moon with respect to a node, is the same as the longitude of the Sun with respect to the same or opposite node, the latter must be 12° for the occurence of a lunar eclipse. But as the difference between the mean and true Suns is about 2°, the longitude is stipulated as 14°. In other words, for the occurence of a lunar eclipse, the longitude of the Sun on the full-Moon day with respect to the nearer node shall be less than 14°. To compute this longitude of the Sun with respect to the nearer node on a full-Moon day, we are given the subse- quent procedure indicated in the verse. In 53433500000 lunations of the Kalpa, the sum of the sidereal revolutions of the Sun and the Node (Rāhu) (Sum because Rāhu has a retrograde motion) is equal to 455231168 which is equal to 455231168 × 12 = 54627734016 Rasis. Then in one lunation what will be the increase of the longitude with respect to the Node? The result is 54627734016 / 53433300000 = 1 Rasi + 3583302048° / 5343330000 (= 74652126 / 111319375) dividing by 48 both the numerator and denominator. Taking the first two digits in the numerator and denomi- nator of the fraction the fraction is approximately equal to 74/111 or 2/3. Taking this as a convergent we make amends for the roughness as follows. 74652126 / 111319375 = 2/3 (1 + 1/λ) ∴ λ = (2 × 111319375) / (3 × 74652126 — 2 × 111319375)