भारतकोश
ब्राह्मस्फुटसिद्धान्त (ब्रह्मगुप्त - शून्य, कुट्टक, बीजगणित एवं सम्पूर्ण २१ अध्याय सान्वय सटीक)

ब्राह्मस्फुटसिद्धान्त (ब्रह्मगुप्त - शून्य, कुट्टक, बीजगणित एवं सम्पूर्ण २१ अध्याय सान्वय सटीक)

Brahmasphuta Siddhanta of Brahmagupta with Commentary

आचार्य ब्रह्मगुप्त द्वारा

DevanagariHindipublished737 पृष्ठ

पृष्ठ 185, कुल 737 में से

संदर्भ में पढ़ें
पृष्ठ 185

CELESTIAL AND POLAR LONGITUDE 143 In order to find σN, he would multiply σK by (R cos σKP) / R ; according to him, σN = (σK × R cos σKP) / R + KH¹ This is a decided improvement on Brahmagupta's corres- ponding rule. The declination σN obtained would be very nearly accurate. Having obtained σN, Bhāskara² then directs the finding of NH, thus, NH = (σK × R sin σKP) / (R cos σN) He then directs the finding of MK on the ecliptic of which NH is the projection by means of the times of rising of the signs of the zodiac on the equator. Thus, the Indian methods show a beginning and develop- ment only. The Greek method as given by Ptolemy is mathe- matically accurate. Greek Method³ To transform the celestial longitude and celestial latitude to right ascension and declination. Let the great circle ΠσK meet the equator at Δ. Ptolemy would then from the given value of γK, find γΔ and ΔK by using his tables for the rising of signs of the zodiac on the equa- tor. He then takes ΠPσ for the triangle and γNΔ Q for the transversal. The Menelaus' Equation, then, is (sin ΠQ / sin QP) × (sin PN / sin Nσ) × (sin σΔ / sin ΔΠ) = 1² Here ΠQ = 90° + ω, QP = 90°, PN = 90°; σΔ = σK + KΔ. ΠΔ = 90° + KΔ, whence Nσ is obtained. He next takes PNQ for the triangle and ΠσΔ for the trans- versal,