पञ्चसिद्धान्तिका (आचार्य वराहमिहिर - सूर्य, रोमक, पौलिश, वासिष्ठ एवं पितामह सिद्धान्त)

XII.3 XII. PAITĀMAHA SIDDHĀNTA 243 Example 1. Compute the ‘days from epoch’ according in the Paitāmaha, for the sunrise of calendrical date eleventh of the light fortnight of Kārttika, in the elapsed Śaka year 426. (i) (426 − 2) ÷ 5 = 424 ÷ 5. Here the remainder is 4, the years gone, in the current yuga. The fifth, Idvatsara is current. (ii) Counting from Māgha, 9 months have elapsed before (Kārttika), in the current year. ∴ the solar months gone = 4 × 12 + 9 = 57. (iii) Intercalary months = 57/30, = 1 27/30 (quotient = 1) (iv) Lunar months gone = 57 + 1 = 58. (v) The calendrical tithis gone in the month are 10. ∴ the total tithis gone = 58 × 30 + 10 = 1750. (vi) Omitted tithis = 1750 ÷ 62 = 28 14/62. (The quotient, 28 are the omitted tithis). Since the remainder, 14, minus 10, leaves 4, which is not greater than 46, the calendrical tithi itself is the tithi. (vii) Days from epoch = 1750 − 28 = 1722. [तिथिनक्षत्रादिः] सैक (त्वं) शे द्युगुणे तिथिर्भमार्कं नवाहते 'ऽक्ष्यर्कैः' । ‘दिग्रस’भागैः सप्तभिरूनं शशिभं धनिष्ठाद्यम् ॥ ३ ॥ Tithi, Nakṣatra etc. 3. Add to the ‘days’ a sixty-first part of itself. The total tithis are got, (which, divided out by thirty, leaves the tithis in the month). Multiply the ‘days’ by 9, and divide by 122. The total nakṣatras are got, (which, divided out by 27, gives its actual nakṣatra, reckoned from Śraviṣṭhā). Multiply the ‘days’ by 7 and divide by 610. Subtract this from the ‘days’. The remainder are the total nakṣatras of the Moon, (which, divided out by 27 and the remainder counted from Śraviṣṭhā, is the Moon's nakṣatra). The following is to be done:– (i) Tithi = ‘days’ + ‘days’ ÷ 61. (This, divided out by 30, and the remainder counted from śukla-pratipad, is the tithi proper). (ii) Sun’s nakṣatra = ‘days’ × 9 ÷ 122. (This, divided out by 27 and the remainder counted from Śraviṣṭhā, is the Sun’s nakṣatra). (iii) Moon’s nakṣatra = ‘days’ − ‘days’ × 7 ÷ 610. (This, divided out by 27 and the remainder counted from Śraviṣṭhā, is the Moon’s nakṣatra). Example 2. For the date of Ex. 1, find the tithi etc. The ‘days’ got there are 1722. (i) Tithi = 1722 + 1722 ÷ 61 = 1722 + 28 14/61 = 1750 14/61. Divided out by 30, the remainder is 10 14/61. ∴ the 10th Tithi of the light fortnight is gone, and 14/61 of Ekādaśī has gone at sunrise. 3. Quoted by Utpala on BS 8.22. 3a. A.B. सैकत्र्यंशत्वं (B.न्वं) चेद्युगणे; C. सैकषष्ट्यंशे द्युगुणे; D. सैकषडंशे द्युगणे; U. सैकत्रिशे b. A.B. भमार्कनचा (B. वा) हस्तेऽर्कैः (B. हस्तेष्टकैः); U. ॰नवाहतो॰ c. A.B. दिग्रह; D. भक्तैः d. A. नूनं A. धनिष्ठाद्यं; B2. धनीष्ठाधं