पञ्चसिद्धान्तिका (आचार्य वराहमिहिर - सूर्य, रोमक, पौलिश, वासिष्ठ एवं पितामह सिद्धान्त)

XVIII.20 XVIII. VĀSIṢṬHA-PAULIŚA – RISING AND SETTING 327 I shall now give an example, to make the method clear. Example: Find true Saturn at 5000 days gone from epoch. i. Days 5000 To be subtracted 150-20

Divided by 378 4849-40 (12 = full cycles gone) 313-40 = (Remaining days) Days to be deducted 10/12 : 1-12

312-28 (corrected remainder) ii. Padas at 0 day of the 13th cycle: (89 + 12 × 9) / 256 = 197 remainder Mean longitude = 197 padas = 9ʳ 7° 2′ 197 = 30 + 127 + 40 (in the third sector) Eq. cent. corrected mean longitude:- = 1ʳ 15° 51′ + 5ʳ 27° 34′ + (2037 + 2 × 40) 40′ ÷ 27 = 1ʳ 15° 51′ + 5ʳ 27° 34′ + 1ʳ 22° 16′ = 9ʳ 5° 41′ Eq. cent. = 9ʳ 5° 41′ − 9ʳ 7° 2′ = −1° 21′ iii. Padas at 378 days gone in the cycle = 197 + 9 = 206 Mean longitude = 206 padas = 9ʳ 19° 41′ 206 padas = 30 + 127 + 49 (in the third sector) Eq. cent. corrected mean longitude = 1ʳ 15° 51′ + 5ʳ 27° 34′ + (2037 + 2 × 47) 47′/27 = 9ʳ 18° 0′ Eq. cent. = 9ʳ 18° 0′ − 9ʳ 19° 41′ = −1° 41′ Interpolated for days 312-28, the eq. cent = −1° 21′ − 0° 17′ = −1° 38′. iv. Correcting the remaining days 312-28 by this, 312-28 + 1-38 = 314-6 days, to be used to find anomaly of conjunction. v. 36 days +3° 7 ... + 0°.35′ Mean Sat. at 0 day 9ʳ 7° 2′ 16 ... + 1° 20′ Eq. cent − 1° 38′ 56 ... + 3° 42′ An. of conj. + 7° 40′ 55 ... − 3° --------------------------- 60 ... − 4° True Saturn = 9ʳ 13° 4′ Remaining 84-6 + 6° 1′ ---------------------------

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314-6 + 7° 40′ As per Ephemeris: 9ʳ 11°.7 (sāyana)

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Mars As indicated earlier, Mars, like Mercury, needed elaborate treatment owing to certain peculiarities about it, and so had been reserved by VM to the end of PS. The synodic period of